A simple pendulum with length L and mass m of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The tension $T$ in the string at the lowest point is given by $T - mg = \frac{mv^2}{L}$,where $v$ is the velocity at the lowest point.For a simple

Vedclass · Accepted Answer

$mg\left[ {1 + {{\left( {\frac{A}{L}} \right)}^2}} \right]$

Vedclass · Answer

(B) The tension $T$ in the string at the lowest point is given by $T - mg = \frac{mv^2}{L}$,where $v$ is the velocity at the lowest point.For a simple pendulum,the maximum velocity $v_{\max} = A\omega$,where $\omega = \sqrt{\frac{g}{L}}$.Thus,$v_{\max}^2 = A^2\omega^2 = A^2 \left(\frac{g}{L}\right)$.Substituting this into the tension equation:$T_{\max} = mg + \frac{m(A^2 g/L)}{L} = mg + \frac{mgA^2}{L^2}$.Factoring out $mg$,we get $T_{\max} = mg \left[ 1 + \left( \frac{A}{L} \right)^2 \right]$.

$A$ simple pendulum with length $L$ and mass $m$ of the bob is vibrating with an amplitude $A$. The maximum tension in the string is

Similar Questions

Two pendulums begin to swing simultaneously. The first pendulum makes $11$ full oscillations when the other makes $9$. The ratio of the lengths of the two pendulums is

$A$ lift is descending with an acceleration of $g/3$. What will be the time period of a simple pendulum suspended from its ceiling if its time period in a stationary lift is $T$?

$A$ pendulum clock is running fast. To correct its time,we should

In an elevator,a spring clock of time period $T_S$ (mass attached to a spring) and a pendulum clock of time period $T_P$ are kept. If the elevator accelerates upwards,what happens to their time periods?

Vedclass Test Series

Exam Paper Generator

Online Exam Module